Answer:
x=2
Step-by-step explanation:
6x+11-4x=15
2x+11=15
2x=4
x=2
Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
7 times 6 is 42
91 divided by 7 is 13
B a counterclockwise rotation about the origin of 90°
under a counterclockwise rotation about the origin
a point ( x , y ) → (- y, x)
figure Q to figure Q'
( 4,2 ) → (- 2, 4 )
(7, 5 ) → (- 5, 7 )
(3, 7 ) → (- 7 , 3 )
(2, 4 ) → (- 4, 2 )
(5, 4 ) → (- 4, 5 )
the coordinates of the original points of the vertices of Q map to the corresponding points on the image Q'
Answer:
B) 112 cm²; 336 cm²
Step-by-step explanation:
The lateral area would be without the bases. In this case, the bases are the top and the bottom
Lateral Area
(2)(2.54)(8) = 40.64
(2)(2.54)(14) = 71.12
Add together and get 111.76 cm²
Surface Area
LA + Bases
<em>Bases</em>
(2)(14)(8) = 224
Add with lateral area and get 335.76 cm²