300,000,000+60,000,000+2,000,000+31,000+1000+100
Answer:
John need to get 293 in his next game to bring his average up to 183.
Step-by-step explanation:
John starts with N games played and averaging 177 points per game.
In game N+1, John scored 199 points.

So, John has now played (N+1) = 22 games.
We need to know what score John needs in game 23 to bring his average to 183.

Hello from MrBillDoesMath!
Answer:
x = 10
Discussion:
A plane triangle contains 180 degrees. Adding the angles in the triangle shown in #8 gives
(4x + 7) + (3x + 13) + 90 = 180
Note the "right angle" shown in the triangle has been replaced by its 90 degree equivalent in the above equation.
Combining like terms gives
( 4x + 3x) + (7 + 13) + 90 = 180
7x + 20 + 90 = 180 => (subtract 90 from each side)
7x + 20 + 90 - 90 = 180 - 90 = 90 =>
7x +20 = 90 => (subtract 20 from each side)
7x + 20 -20 = 90 -20 =>
7x = 70 =>
x 70/7 =10.
Thank you,
MrB
Since you don't show the graph, all I can do is to tell you how to identify which function is parallel to the x-5y=8.
First let's rearrange the function.
x-5y=8
5y=x-8
y=1/5x-8/5.
Thus, it gives us the slope of the function, which is 1/5.
And the function that is parallel to the graph would have the SAME slope. Which is 1/5. So all you need to do is to find which function has the SAME SLOPE, in this case: 1/5.
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
PLEASE SEE ATTACHED IMAGE.
Part 1:
we must see in the graph the axis of symmetry of the given parabola.
The axis of symmetry is the following vertical line:
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We have that when evaluating t = 1, the function is:

To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, we have from the graph that:

Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds