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3 years ago

Help me ASAP for this question you have to pick more than one

Mathematics

1 answer:

abruzzese [7]3 years ago

5 0

Answer:

A) 56/x=85/100

C) 56=(0.85)w

Step-by-step explanation:

Sonce 56/.85=65.88, we look for the two that have that answer.

A) 56/x=85/100

cross multiply 5600=85x

divide by 85

x=65.88 - YES

B) p=(0.85)56=47.6 - NO

C) 56=(0.85)w

Divide both sides by 0.85=65.88 - YES

D) x/56=85/100

100x=4760=47.6 - NO

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Given: ∠ A = ∠ C, E is the midpoint of AC Prove: △AEB △CED

bija089 [108]

Answer:

Step-by-step explanation:

3.AE = CE E is the midpoint of AC

4. ∠AEB = ∠CED Vertically opposite angles are equal

5. ΔAEB = ΔCED ASA congruence

4 0

3 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$