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pantera1 [17]
3 years ago
5

What is the purpose of learning polynomials?

Mathematics
1 answer:
jasenka [17]3 years ago
6 0
There is none.  Unless you count filling up random space in the school year!
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What is the area of a rectangle with vertices at (−3, −1) , (1, 3) , (3, 1) , and (−1, −3) ?
wel
I hope this helps you

7 0
3 years ago
Of the songs in Brianna's music library, 1/3 are rock songs. Of the rock songs, 7/10 feature a guitar solo. What fraction of the
Marat540 [252]

Answer:

7/30 of her music library

Step-by-step explanation:

We are looking for 7/10 of 1/3. In this case this "of" means we will multiply the two fractions. To multiply fractions, we multiply

top × top

and

bottom × bottom

1/3 × 7/10

is 1×7 on top, and

3×10 on the bottom.

= (1×7)/(3×10)

= 7/30

7/30 cannot be simplified, so that is the answer.

6 0
2 years ago
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
To model 15 – 11 on a number line, begin at _______ and travel 11 units to the left.
Vadim26 [7]

The answer is 15 cause you start at 15 and go from there


7 0
3 years ago
Read 2 more answers
Enter the trigonometric equation you would use to solve for x in the following right triangle. Do not solve the equation.
Blababa [14]

Equation:

tan(x) = \frac{opp}{adj}

7 0
3 years ago
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