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2 years ago

HELPPP IT WOULD BE APPRECIATED :)

Mathematics

1 answer:

ira [324]2 years ago

3 0

Step-by-step explanation:

HELPPP IT WOULD BE APPRECIATED :) gHjajjak\ajjjjjnjajjajjajajjaiajjaja

PAGAL KUTTA

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Look at image it will give you the qeustion

bixtya [17]

Answer:

Step-by-step explanation:

I would think be because it's the only one that crosses the rest don't

3 0

2 years ago

The price of a technology stock was $9.74 yesterday. Today, the price fell to $9.67. Find the percentage decrease. Round your an

agasfer [191]

% change = (new value - old value)/(old value) * 100%
.. = (9.67 -9.74)/9.74 * 100%
.. = -0.07/9.74 * 100%
.. = -0.7%

The decrease is 0.7%.

5 0

3 years ago

How is this problem factored? 35x^2-57x-44

faust18 [17]

You can use the quadratic formula with it which will be easier
or simple factoring
it will be (5x-11)(7x+4)

7 0

2 years ago

WV is the

PilotLPTM [1.2K]

Answer:

WV is the perpendicular bisector of UT.

3 0

3 years ago

2v^2-12 =-12v <br> Would really appreciate it loves❤️

Black_prince [1.1K]

For this case we have the following equation:

$2v ^ 2-12 = -12v$

Rewriting we have:

$2v ^ 2 + 12v-12 = 0$

Dividing by 2 to both sides of the equation:

$v ^ 2 + 6v-6 = 0$

We apply the quadratic formula:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

We have to:

$a = 1\\b = 6\\c = -6$

Substituting:

$x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}$

Thus, we have two roots:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

ANswer:

$x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}$

7 0

2 years ago