<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>
What is the 5th term of an AP 2 , 14 ....98 .
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>
- <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>
<h3><u>Solution </u><u>:</u><u>-</u></h3>
<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>
<u>Therefore</u><u>, </u>
<u>Here</u><u>, </u>
Common difference of an AP
Thus, The common difference is 12
<u>Now</u><u>, </u>
We know that,
Hence, The 5th term of given AP is 50
10 20 30 40 50
15 30 45 55 70
20 40 60 80 100
24 48 72 96 120
Answer:
23, 25
Step-by-step explanation:
let the first number be represented as A, since there are two odd numbers, the second number would be A + 2
A + A+2 = 48
2A + 2 = 48
2A = 48 - 2
2A = 46 ( divide both sides by 2)
A = 23
since we know the next number to be A + 2
= 23 + 2 = 25
the two numbers are 23 and 25
Answer:
V(max) = 8712.07 in³
Dimensions:
x (side of the square base) = 16.33 in
girth = 65.32 in
height = 32.67 in
Step-by-step explanation:
Let
x = side of the square base
h = the height of the postal
Then according to problem statement we have:
girth = 4*x (perimeter of the base)
and
4* x + h = 98 (at the most) so h = 98 - 4x (1)
Then
V = x²*h
V = x²* ( 98 - 4x)
V(x) = 98*x² - 4x³
Taking dervatives (both menbers of the equation we have:
V´(x) = 196 x - 12 x² ⇒ V´(x) = 0
196x - 12x² = 0 first root of the equation x = 0
Then 196 -12x = 0 12x = 196 x = 196/12
x = 16,33 in ⇒ girth = 4 * (16.33) ⇒ girth = 65.32 in
and from equation (1)
y = 98 - 4x ⇒ y = 98 -4 (16,33)
y = 32.67 in
and maximun volume of a carton V is
V(max) = (16,33)²* 32,67
V(max) = 8712.07 in³