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Olenka [21]
3 years ago
6

What patter do you see in the coordinatinates​

Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0
Hey y’all are going back to the 56
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They all have to be simplified
deff fn [24]
13. 1111111 / 2000000
14. 209 / 90
15. 26 / 3
16. 22590909 / 5000000
(mark brainliest is right pls)


4 0
3 years ago
Read 2 more answers
Helpppppppppppppppppppppppppp!!!!!!
Alex17521 [72]

Answer:

y =x

Step-by-step explanation:

the cordinate  of y = x is the same line going form top to bottom

7 0
3 years ago
PLEASE HELP Which values for A and B will create infinitely many solutions for this system of equations? 4 x minus A y = 15. Neg
wel

Answer:

the answer is C

Step-by-step explanation:

you should message me

3 0
3 years ago
Read 2 more answers
Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the
VikaD [51]

In general, the exponential growth function is given by the formula below

f(x)=a(1+r)^x

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}

And 1976 is n=16

\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}

Solve the two equations simultaneously, as shown below

\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}

Solving for a,

\begin{gathered} r=0.0464078 \\ \Rightarrow a=\frac{1.6}{(1+0.0464078)^8}=1.113043\ldots \end{gathered}

a) Thus, the equation is

\Rightarrow f(n)=1.113043\ldots(1+0.0464078\ldots)^n

b) 1960 is n=0; thus,

f(0)=1.113043\ldots(1+0.0464078\ldots)^0=1.113043\ldots

The answer to part b) is $1.113043... per hour

c)1996 is n=36

\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}

The model prediction is above $5.15 by $0.55 approximately. The answer is 'below'

4 0
1 year ago
The diagram shows a sector of a circle radius 10cm. Find the perimeter of the sector, giving your answer correct to 1 decimal pl
qwelly [4]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Anyway, I'll help you either way. A sector is a region of a circle between two radii. Let's assume the sector as:

s=25\pi cm^2

Then, we can find the central angle by the following equation:

s=\frac{\theta}{360}\times\pi r^{2} \\ \\ r=10cm \\ \\ s=25\pi cm^2 \\ \\ \\ So: \\ \\ \frac{25\pi(360)}{10^2\pi}=\theta \\ \\ \theta = 90^{\circ}

But:

90^{\circ}=\frac{\pi}{2}

Then:

C:Perimeter \ of \ sector \\ \\ \\ C=\theta r \\ \\ C=\frac{\pi}{2}(10) \\ \\ C=5\pi cm \approx \boxed{15.7cm}

6 0
4 years ago
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