Answer:
The values of p in the equation are 0 and 6
Step-by-step explanation:
First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p
2
−7p−4=(2p+1)(p−4)
So then the equation looks like:
\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}
2p+1
p
−
(2p+1)(p−4)
2p
2
+5
=−
p−4
5
To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:
\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}
(2p+1)(p−4)
p
2
−4p
−
(2p+1)(p−4)
2p
2
+5
=−
(p−4)(2p+1)
10p+5
Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.
(p^2-4p)-(2p^2+5)=-(10p+5)(p
2
−4p)−(2p
2
+5)=−(10p+5)
Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p
2
−4p)−(2p
2
+5) first:
(p^2-4p)-(2p^2+5)=-p^2-4p-5(p
2
−4p)−(2p
2
+5)=−p
2
−4p−5
-p^2-4p-5=-10p+5−p
2
−4p−5=−10p+5
Combine like terms:
-p^2-4p+0=-10p−p
2
−4p+0=−10p
-p^2+6p=0−p
2
+6p=0
Factor:
p=0, p=6p
Answer:
c² - 63
Step-by-step explanation:
4c - 10 = 30
3c ÷ 3 = 10
c² - 63 = 37
c² ÷ 10 = 10
Since c² - 63 = 37 and c + 25 = 35, 37 is greater than 35 so it would make sense to choose c² - 63 as the answer.
c + 25 < 37
I hope this helps you :D
The missing values are 28° and 62°
<h3>What are perpendicular lines?</h3>
Perpendicular lines are said to be two lines that intersect or meet each other at right angles, that is 90 degrees.
From the information given, we have that;
Line AC ⊥ Line BE
Where:
- m ∠ ADE = (x + 5)°
- m ∠ DBE = (3x - 7)°
Hence,
x + 5 + 3x - 7 = 90
collect like terms
4x = 90 + 2
4x = 92
Make 'x' the subject
x = 92/ 4
x = 23
For the missing values
m ∠ ADE = (x + 5)° = ( 23 + 5) = 28°
m ∠ DBE = (3x - 7)° = (3(23) - 7) = 62°
Thus, the missing values are 28° and 62°
Learn more about perpendicular lines here:
brainly.com/question/17683061
#SPJ1
Answer:
393.9
Step-by-step explanation:
Multiply 30.3 with 13.. Will get the answer 393.9
30.3= x / 13
X = 30.3 x 13
