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kirill [66]
3 years ago
13

The measure of the angles of a pentagon are (x - 5), (x - 6), (2x - 7), x° and (2x - 2). Find the

Mathematics
1 answer:
zzz [600]3 years ago
6 0

Answer:

x=80 degree

Step-by-step explanation:

(x-5)+(x-6)+(2x-7)+x+(2x-2)=540 degree (sum of interior angles of a pentagon)

x-5+x-6+2x-7+x+2x-2=540

7x-20=540

7x=540+20

x=560/7

x=80 degree

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HELP!! Suppose the area of a circle is 201.0624 square feet. What's the diameter of the circle? (Use π = 3.1416.)
Liono4ka [1.6K]

<u>Answer</u>

C. 16 feet


<u>Explanation</u>

The area of a circle is given by the formula:

Area = πr² Where r is the radius of the circle and π = 3.1416

201.0624 = 3.1416 × r²

r² = 201.0624/3.1416

    = 64

r = √64

   = 8 feet

Diameter is twice the radius.

∴ diameter = 2r

                  = 2 × 8

                  = 16 feet


         

3 0
3 years ago
ameena is printing the class newsletter there are 8 pages in the newsletter and she needs 74 copies . Each package of paper cont
deff fn [24]

Ameena will need a total of 7 packages of paper. (Not every sheet will be used, but having just 6 packages won’t give here enough paper to use). Here’s why:

If she needs 74 copies of the newsletter, and each newsletter contains 8 pages, then she will need a total of 592 pieces of paper (74*8=592). 7 packages will give her 630 pieces of paper to use (90*7=630). 6 packages would only give her 540 pieces of paper (90*6=540), so she needs 7 total packages of paper.

4 0
3 years ago
4. The two trapezoids below are similar. What is the
nalin [4]
It has to B A because always come first
7 0
2 years ago
To which court does an appeal go after the US court of appeals?
zavuch27 [327]

An appeal is available if, after a trial in the U.S. District Court, the losing side has issues with the trial court proceedings, the law that was applied, or how the law was applied.

8 0
3 years ago
Read 2 more answers
When 12x² + kx + 3 and 3x³ + (3k + 2)x² + 28x +17
Naily [24]

Answer:

\boxed{\sf \ \ \ k=5 \ \ \ }

Step-by-step explanation:

Hello,

We know that for a real, the polynomial P(x) divided by (x-a) the remainder is P(a)

and as

3x+2=03x=-2x=\dfrac{-2}{3}

so we need

12(\dfrac{-2}{3})^2+k(\dfrac{-2}{3})+3=3(\dfrac{-2}{3})^3+(3k+2)(\dfrac{-2}{3})^2+28\dfrac{-2}{3}+17\\ \ multiply \ by \ 9\\ 12*4-6k+27=-8+4(3k+2)-28*2*3+17*9\\ -6k+48+27=-8+12k+8-168+153\\ -6k+75=12k-15\\ 18k=75+15=90\\ k = \dfrac{90}{18}=\dfrac{15}{3}

hope this helps

7 0
3 years ago
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