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aev [14]
3 years ago
7

What is the probability of not rolling factors of 4 on both dice ?

Mathematics
1 answer:
galben [10]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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valina [46]

2) longest line is (-1, -3) and (-1, 7)

3) (-1, -3), (-6,2), and (2,4)

5 0
3 years ago
A carpenter needs to cut down piece of wood that is 5.6 feet long to 1.71 feet . What is the measurement of the left over piece
7nadin3 [17]
Subtract the two numbers to find the measurement of the leftover piece
5.6 - 1.71 = 3.89 feet
7 0
3 years ago
If (x+4)*2=49 and x<0, what is the value of x
Nady [450]

Answer:

41 is the answer bro thanks

7 0
3 years ago
Which of the following expressions is this one equivalent to?
schepotkina [342]

Answer: C. x-2

Step-by-step explanation:

We have the following expression:

\frac{x^{4} -2x^{3} +x-2}{x^{3}+1}

Factoring in the numerator:

\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}

Factoring again in the numerator with common factor x^{3}+1:

\frac{(x^{3}+1)(x-2)}{x^{3}+1}

Simplifying:

x-2

Hence, the correct option is C. x-2

3 0
3 years ago
Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r
koban [17]

The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

Step-by-step explanation:

The given is,

                     A new virus with a decay rate of 19% per hour  

                    They start with 300 viruses

Step:1

                  Formula to calculate the viruses at decay rate,

                                                  y = A(1-r)^{t}............................(1)

                 Where, y - No of viruses after given time

                             A - Viruses at initial stage

                              r - Decay rate

                              t - No. of hours

                 From the given,

                              A = 300

                               r = 19% per hour

                               t = 7 hours

                Equation (1) becomes,

                                            y = 300(1-0.19)^{7}

                                               = 300(0.81)^{7}

                                               = 300(0.228767)

                                               = 68.63

               Viruses of 7 hours ≅ 69 viruses

                                                     ( or )

Step:1

        For 1st hour,

          = (No.of viruses in hour) - (No,of viruses in last hour × Decay rate )

              = (300)-(300 × 0.19)

              = 300 - 57

              = 243

       For 2nd hour,

              = (243)-(243 × 0.19)

              = 243 - 46.17

              = 196.83

      For 3rd hour,

              = (196.83)-(196.83 × 0.19)

              = 196.83 - 37.39

              = 159.4323

       For 4th hour,

              = (159.4323)-(159.4323 × 0.19)

              = 159.4323 - 30.2921

              = 129.1402

      For 5th hour,

              = (129.1402)-(129.1402 × 0.19)

              = 129.1402 - 24.5366

              = 104.6035

     For 6th hour,

              = ( 104.6035)-( 104.6035 × 0.19)

              =  104.6035 - 19.8747

              = 84.7288

     For 7th hour,

              = (84.7288)-(84.7288 × 0.19)

              =  84.7288 - 16.0984

              = 68.63 viruses

Result:

          The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

7 0
3 years ago
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