Given the half like of a material to be 8.3 hours and the amount of iron-52 left after t hours is modeled by the equation $A(t) = A_0 a^{t}$ , we can get A(t) as shown;

At t = 8.3 hours, A(8.3) = 1/2

Initially at t = 0; A(0) = 1

Substituting this values into the function we will have;

$\frac{1}{2} = 1 * a^{8.3}\\\\Taking \ the \ log \ of\ both \ sides;\\\\log(\frac{1}{2} ) = log(a^{8.3} )\\\\log(\frac{1}{2} ) = 8.3 log(a)\\\\\fr-0.30103 = 8.3 log(a)\\\Dividing\ both\ sides\ by \ 8.3\\\\\frac{-0.30103}{8.3} = log(a)\\\\log(a) = - 0.03627\\\\a =10^{-0.03627} \\\\a = 0.919878 (to\ 6dp)$

4 0

3 years ago

Mark borrowed $5,500 at 11.5% interest for 5 years what is his monthly payment

Firlakuza [10]

Marks monthly payment would be $1,226.50 monthly. If mark is borrowing $5,500 plus a 11.5% interest he be paying $1,226.50

5 0

3 years ago

Read 2 more answers

The perimeter of a rectangle is 48 in. if the length is twice the width, what is the length of the rectangle?

Scilla [17]

B. 16

if the length of each side is 16in, the total length would be 32in.
(16 x 2 = 32)
because the length is equal to twice the width, divide 32 by 2
(32/2 = 16)

16 + 32 = 48

6 0

3 years ago

Help ASAP . i will give you points please !​

Help ASAP . i will give you points please !