Answer:
Step-by-step explanation:
- given ap series : 8,3,-2,-7,-12....up to n terms
[the second term should be +3 or else it wont form AP series]
first term in the series: 8
common difference : 3-8 = -5
total terms : n
- the formula for sum of n terms in an ap =
![\frac{n}{2} [2a+(n-1)d]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2a%2B%28n-1%29d%5D)
a: first term
d: common difference
n : total terms
- by substituting value in the above formula,
- sum of the A.P:
![\frac{n}{2} [2(8)+(n-1)-5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2%288%29%2B%28n-1%29-5%5D)
![\frac{n}{2} [16+(n-1)(-5)]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B%28n-1%29%28-5%29%5D)
![\frac{n}{2} [16+-5n+5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B-5n%2B5%5D)
![\frac{n}{2} [21+-5n]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B21%2B-5n%5D)
=
Answer:
Yes
Step-by-step explanation:
9x - 4x = 2
5x = 2
x = 2/5
x = 0.4
Answer:
The answer to the question provided is -62.
Remember that an absolute value is the measure of something's distance from 0 on the number line. A key piece of that idea is that distances cannot be negative.
So, any absolute value set equal to or less than 0 or any negative number cannot have any solution.
Working out way up from the bottom...
That bottom one, is clearly an issue, since you have an absolute value set less than -2.
To decide on the others, you need to get the absolute value by itself.
On the third inequality, you need to divide by -2 to get the abs val by itself. When you do that, you'll end up with |3x-5| ≤ -3/2. That's a problem, so that won't have any solution.
On the second one, you'd start by subtracting 17 from both sides and you'd get |3x-6| > -2. That'll always be true, since an absolute value is always 0 or positive.
And you have the same thing with the first inequality too, that it's already set > a negative, so it's always true.
So, just the last two will not have solutions.
