Answer:
(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.
Step-by-step explanation:
Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.
Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.
Test statistic (t) = (sample mean - population mean) ÷ sd/√n
sample mean = 3.24 minutes
population mean = 3.3 minutes
sd = 0.4 minutes
n = 62
degree of freedom = n - 1 = 62 - 1 = 71
significance level = 0.08
t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2
The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654
Conclusion:
Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.
Answer:
28
Step-by-step explanation:
10 - (-18)
=> 10 + 18
=> 28
Hoped this helped.
Answer:
When c and a are positive or both are negative
Step-by-step explanation:
negative times negative equals positive so if a was negative and c was negative -a*-c= ac
Of course positive times positive equals negative so if a and c were positive we could do
a*c= ac
Hope I could help !
The population density of Romania in 1997 given its area and the population is 95 people per square km.
<h3>What is the population density?</h3>
Population density is the number of people that live in a square kilometer of an area. It is determined by dividing total population by total area.
Population density = population / area
22.600,000 / 237301 = 95 people per square km
To learn more about population density, please check:
brainly.com/question/3704320
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Answer:
(a) The probability of having exactly four arrivals during a particular hour is 0.1754.
(b) The probability that at least 3 people arriving during a particular hour is 0.7350.
(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.
Step-by-step explanation:
(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:
The probability of having exactly four arrivals during a particular hour is 0.1754.
(b) The probability that at least 3 people arriving during a particular hour can be written as
Using
We get
The probability that at least 3 people arriving during a particular hour is 0.7350.
(c) The expected arrivals in a 45 minute period (0.75 hours) is
