Answer:
z (min) = 705
x₁ = 10
x₂ = 9
Step-by-step explanation:
Let´s call x₁ quantity of food I ( in ou ) and x₂ quantity of food II ( in ou)
units of vit. C units of vit.E Cholesterol by ou
x₁ 32 9 48
x₂ 16 18 25
Objective function z
z = 48*x₁ + 25*x₂ To minimize
Subject to:
1.-Total units of vit. C at least 464
32*x₁ + 16*x₂ ≥ 464
2.- Total units of vit. E at least 252
9*x₁ + 18*x₂ ≥ 252
3.- Quantity of ou per day
x₁ + x₂ ≤ 35
General constraints x₁ ≥ 0 x₂ ≥ 0
Using the on-line simplex method solver (AtoZmaths) and after three iterations the solution is:
z (min) = 705
x₁ = 10
x₂ = 9
V^2/(1-v^2/c^2)=R
v^2=R(1-v^2/c^2)
v^2=R-Rv^2/c^2
v^2-Rv^2/c^2=R
v^2(1-R/c^2)=R
v=sqrt(R/(1-R/c^2))
where R was original right side, dont forget plus minus
The answer in decimal form is <span>: -1.6</span>
Answer:
Hours slept = 6 hours
Hours awake = 18 hours
Step-by-step explanation:
Sasha got 1 hour of sleep for every 3 hours she was awake.
So,
<u>This means:</u>
Slept : Awake = 1 : 3
Total hours in a day = 24 hours
<u>Let </u>
Hours slept = 1x and hours awake = 3x
<u>Hence,</u>
1x + 3x = 24 hours
4x = 24
Divide both sides by 4
x = 24 / 4
x = 6
<u>So,</u>
Hours slept = 1(6) = 6 hours
Hours awake = 3(6) = 18 hours
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>