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gavmur [86]
3 years ago
10

The three basic processes of memory are ______.

Computers and Technology
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

The correct answer is letter "C": encoding, storage, retrieval.

Explanation:

In psychology, the stages of memory are <em>encoding, storage, </em>and <em>retrieval</em>. Encoding refers to changing the information as it is received so it can be stored in the memory and imply inputs in three kinds: <em>visual (pictures), acoustic (sounds), </em>and<em> semantic (meaning)</em>. Storage is the stage in which the input is retained in the memory, where it is stored, and for how long. Finally, retrieval implies organizing information stored in the memory to recall it.

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Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
terms found in provider documentation (e.g., difficult, extensive, or unusual) would support adding modifier to a cpt code.
Oksi-84 [34.3K]

The terms found in provider documentation (e.g., difficult, extensive, or unusual) would support adding modifier -22 to a cpt code.

<h3>What are cpt code?</h3>

Current Procedural Terminology (CPT) is known to be a kind of  a medical code set that is known to be used to report any form of medical, surgical, and diagnostic work and services to firms such as physicians, health insurance firms and accreditation firms.

Therefore, Note that the terms found in provider documentation (e.g., difficult, extensive, or unusual) would support adding modifier -22 to a cpt code.

Learn more about documentation from

brainly.com/question/968907

#SPJ1

Terms found in provider documentation (e.g., difficult, extensive, or unusual) would support adding modifier __________ to a CPT code.

3 0
2 years ago
Once an illustration has been decomposed, you can change the color of different items in that illustration.
Delicious77 [7]

Answer:

its true

Explanation: took the quiz

3 0
3 years ago
In the ________ step the data is either written to the file or read from the file.
nexus9112 [7]
I believe the step is <span>Insertion </span>
7 0
3 years ago
How do you get your winkey wet??
Lynna [10]

Answer:

what

Explanation:

what

sorry but what

7 0
2 years ago
Read 2 more answers
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