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nika2105 [10]
4 years ago
8

The computer uses unallocated space for what​

Computers and Technology
2 answers:
Greeley [361]4 years ago
6 0
<h2>Answer:</h2>

Unallocated space is used as <u>a new single partition</u>.

<h2>Explanation:</h2>

The physical space on a hard drive that is not partitioned is considered as unallocated space.  

The programs use the space that is existing in the partitions. Space existing in the partition is termed as allocated space.

So, when there is no partition, the space cannot be used by the programs. This unallocated space is non-existent for the Operating system.

The space in the drive is partitioned during the system installation. In such cases where unallocated space exists, the system can create a new partition through the Disk Management control panel. Right-click on the unallocated space and left click on “New Simple Volume”. This turns all the unallocated space into a single new partition.

finlep [7]4 years ago
3 0

A computer uses unallocated space also know as free space to keep a file that has been deleted in its disk until a new file takes it spot and overwrites it.

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7 0
3 years ago
Write a short program using Python that will:
Alexxx [7]

Answer:

// program in Python to check perfect number

#function to find number is perfect or not

def is_Perfect_Number(n):

   #total variable

   tot = 1

   i = 2

   #sum of all divisor of number

   while i*i<=n:

       if n%i==0:

           tot = tot + i + n/i

       if tot == n and n != 1:

           return 1

       i = i+1  

   return 0

#read until user enter a perfect number

while True:

   #read integer

   num = int(input("Input an integer: "))

   #call the function

   if(is_Perfect_Number(num)):

       print(num,"is perfect number")

       #if perfect number break

       break

   else:

       print(num,"is not a perfect number")

       #ask again

   print("try again.")

Explanation:

Read number from user and then call the function is_Perfect_Number() with  parameter "num".This will find the sum of all divisor of number.If sum is  equal to number then it will return 1 else return 0.If the number is not  perfect then it will again ask to enter a number until user enter a perfect  number.

Output:

Input an integer: 24

24 is not a perfect number                                                                                                

try again.                                                                                                                

Input an integer: 28                                                                                                      

28 is perfect number

6 0
3 years ago
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