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Andrej [43]
3 years ago
7

How do you create a model to solve the problem: 2/3 times 3/4

Mathematics
2 answers:
Darya [45]3 years ago
7 0
3 times four and two times three your answer is one half
hodyreva [135]3 years ago
7 0
You create a model or use the numbers. Like this: 2×3=6 then, 3×4=12 and you have the fraction 6/12
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Qualitative research differs from quantitative research because it a. relies heavily on statistical analysis b. is conducted in
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Answer:

d

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The side of the square is 4 cm since 4x4= 16
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What is the area of triangle ABC?
Ann [662]

Answer:

A = 3 units^2

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
3 years ago
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