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aalyn [17]
4 years ago
15

-y varies inversely with x. When y = 9.6, x = 12. What is the value of k, the constant of inverse variation?

Mathematics
1 answer:
alisha [4.7K]4 years ago
6 0

Question 1:

For this case we have an equation of the form:

y = \frac {k} {x}

Where,

  • <em>k: inverse variation constant. </em>

Then, substituting values we have:

y =\frac {k} {x}

From here, we clear the value of k.

We have then:

k = 9.6 * 12\\k = 115.2

Answer:

the constant of inverse variation is:

k = 115.2

Question 2:

For this case we have:

y = \frac {k} {x}

Where,

  • <em>k: constant of variation. </em>

Then, substituting the value of the constant we have:

y =\frac {5.6} {x}

We now substitute the value of x:

y = \frac {5.6} {4}\\y = 1.4

Answer:

 the value of y when x = 4 is: y = 1.4

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X = y 2 - 1
pochemuha
Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
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Read 2 more answers
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