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aalyn [17]
4 years ago
15

-y varies inversely with x. When y = 9.6, x = 12. What is the value of k, the constant of inverse variation?

Mathematics
1 answer:
alisha [4.7K]4 years ago
6 0

Question 1:

For this case we have an equation of the form:

y = \frac {k} {x}

Where,

  • <em>k: inverse variation constant. </em>

Then, substituting values we have:

y =\frac {k} {x}

From here, we clear the value of k.

We have then:

k = 9.6 * 12\\k = 115.2

Answer:

the constant of inverse variation is:

k = 115.2

Question 2:

For this case we have:

y = \frac {k} {x}

Where,

  • <em>k: constant of variation. </em>

Then, substituting the value of the constant we have:

y =\frac {5.6} {x}

We now substitute the value of x:

y = \frac {5.6} {4}\\y = 1.4

Answer:

 the value of y when x = 4 is: y = 1.4

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Step-by-step explanation:

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2x^2 -18x -2x + 32 = 0

2x^2 -20x + 32 = 0

2x^2 - 16x - 4x + 32 = 0

2x(x -8) -4( x -8) = 0

(2x -4)(x -8) = 0

2x = 4 or x = 8

x = 4/2 or x = 8

hence; x = 2 or 8

Now let’s get the y value

at x = 2, just substitute into any of the 2

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y = -2(2) + 32

y = -4 + 32 = 28

at x = 4

y = -2(4) + 32

y = -8 + 32

y = 24

The points that they will collide are;

(2,28) and (4,24)

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