Answer:
1. cos(F) = 2. 5/13
tan (F) = 3. 12/5
sin (F) = 1. 12/13
2. Sin (R) = 1. 60/68 = 30/34 = 15/17
cos (R) = 2. 32/68 = 16/34 = 8/17
tan (R) = 3. 60/32 = 30/16 = 15/8
Step-by-step explanation:
1 picture:
sin = Opp/Hyp
cos = adj/hyp
tan = opp/adj
cos(F) = 2. 5/13
tan (F) = 3. 12/5
sin (F) = 1. 12/13
2 Picture:
Sin (R) = 1. 60/68 = 30/34 = 15/17
cos (R) = 2. 32/68 = 16/34 = 8/17
tan (R) = 3. 60/32 = 30/16 = 15/8
We know that this is a right triangle, so one of the sides has to be 90 (indicated by the square on the corner) The angles of all triangles must add to exactly 180. Subtract 90 and 35 from 180
If we do that, we get 55. We know that the unknown angle is 55 now. Now, it asks us for b. We can pythagoras theorem which states that (a^2 + b^2 = c^2) We already know c (c is 20) It does not tell us 2 of the sides but we do know that the answer is either B or D.
The side opposite of 90* should be the largest. The size opposite of 55 would be the second largest one. The side opposite of 35 would be the smallest one. Using pythagoras theorem again, I can try plugging in both 11.47 and 16.38 with c^2 - b^2 = a^2
11.47:
400 - 132 =268 (sq root now = 16.37) this would mean that A is larger than B. B should be larger than A. Try the other one
16.37:
400 -268 = 132 (sq root = 16.37) this would mean that B is larger than A which is what we want.
Thus, 16.37 = B and the last option would be correct (D)
Hope this helps, give an honest rating for me please
Answer:
120 cm²
Step-by-step explanation:
From the question;
- Length is 12 cm
- Width is 10 cm
We are required to determine the area of the cross section;
- Note that the cross section is the plane of a solid that remains constant through the solid.
- In this case, the cross section is a rectangle whose dimensions are 12 cm by 10 cm.
But Area of a rectangle = Length × Width
Therefore;
Area of cross section = 12 cm × 10 cm
= 120 cm²
Thus, area of the cross section is 120 cm²
Answer:
Step-by-step explanation:
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Answer:
Step-by-step explanation:
answer is 3