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2 years ago

Explain what Carl did incorrectly

Mathematics

1 answer:

aalyn [17]2 years ago

3 0

At the begging of the problem Carl did not distribute 4&3 and 4&6 he subtracted 4 from 6 which made the entire equation different

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I need to solve this equation, when you answer i would like the steps on how you did it so that i can do problems like this one.

Alla [95]

Answer:

3(3x-1)

Step-by-step explanation:

3(2x-1)+3

3(2x-1x)

3(3x-1)

5 0

2 years ago

A store is having a sale on walnuts and chocolate chips. For 7 pounds of walnuts and 9 pounds of chocolate chips, the total cost

Jlenok [28]

Answer:

Walnuts cost $1.75, chocolate chips cost $2.75

Step-by-step explanation:

<h3>Let the costs be:</h3>

Walnuts - x
Chocolate chips - y

<h3>Set equations as per question</h3>

For 7 pounds of walnuts and 9 pounds of chocolate chips, the total cost is $37:

7x + 9y = 37

For 5 pounds of walnuts and 3 pounds of chocolate chips, the total cost is $17:

5x + 3y = 17

<h3>Solve the system by elimination</h3>

Multiply the second equation by 3 and subtract the first equation, solve for x:

3(5x + 3y) - (7x + 9y) = 3(17) - 37
15x + 9y - 7x - 9y = 51 - 37
8x = 14
x = 14/8
x = 1.75

Find the value of y:

7*1.75 + 9y = 37
12.25 + 9y = 37
9y = 37 - 12.25
9y = 24.75
y = 24.75/9
y = 2.75

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1 year ago

What are the slope and the y-intercept of the linear function that is represented by the table?

uranmaximum [27]

Answer:

x y Negativo tres cuartos Negativo

Step-by-step explanation:

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2 years ago

What is X to the third power plus 125?

iren [92.7K]

Here is your answer wish you the best of luck

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2 years ago

Read 2 more answers

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago