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3 years ago

Please help once again!!! I need it ASAP!!! It's due very soon!!!

Mathematics

2 answers:

Agata [3.3K]3 years ago

6 0

Number 13 is 79° !!!!!!

Aliun [14]3 years ago

4 0

Answer:

1st Question:

m<1 = 90°

m<2= 79°

m<3= 101°

2nd Question:

m<1=97°

m<3=83°

m<6=83°

Step-by-step explanation:

1st Question :

m<1 is a right angle.

m<2 is 79° because of parallel line denote the same angle.

m<3 is 101° because 180°-79°=101°.( As we know sum of angles in a straight line = 18° degree. )

2nd question:

m<1 is 97° because sum of angles in a straight line = 180°

So, 180°-83°=97°

m<3 is 83° because sum of parallel sides are equal.

m<6 is 83° because sum of parallel sides are equal.

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A school band gives a year-end concert. It is held in a 400-seat auditorium. Each concert ticket sells for $10, and 85% of the t

bazaltina [42]

Answer: $3,400

Step-by-step explanation:

There are 400 seats in the auditorium which means that there are 400 tickets to be sold.

85% of these tickets are sold. The number of tickets sold is:

= 85% * 400

= 340 tickets were sold.

Each ticket sells for a total of $10.

The amount of money made from ticket sales is therefore:

= No. of tickets sold * price of ticket

= 340 * 10

= $3,400

6 0

3 years ago

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5 0

3 years ago

Read 2 more answers

Need help on this math study guide

photoshop1234 [79]

2 terms on left side, 3 on right side

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6 0

3 years ago

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

4 years ago

The perimeter of a rectangle is 300 feet. The width of the rectangle is 10 feet more than the length. What is the width of the r

gavmur [86]

300 = 2(x + x + 10)
300 = 2(2x +10)
300 = 4x + 20
4x = 280
x = 70
x + 10 = 80
width = 80ft
answer <span>D) 80 feet</span>

7 0

3 years ago