Answer:
- C-B
- C-C
- C-N
- C-O
- C-F
Explanation:
As we move along to the <u>right in the same period, the electronegativity</u> and <u>the effective nuclear charge values are higher.</u>
The tendency is that <em>the higher these values are, the shorter the bonds will be</em>.
With that information in mind, and looking at the periodic table, the order would be:
- C-B
- C-C
- C-N
- C-O
- C-F
Where the C-F bond is the shortest among them.
I can’t see the picture for some reason
H2SO.Mgslfurmobile phase in this experiment
