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Yuliya22 [10]
3 years ago
15

Please help.... will be awarding brainliest.

Chemistry
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

I have no idea I never figured out how to do that when i learedend it

Explanation:

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mafiozo [28]
Put a picture we can’t see the arrow
7 0
2 years ago
Qué permite las reacciones de redox
liberstina [14]

Explanation:

I am not understanding your question

5 0
2 years ago
A 10 gram sample of iron reacts with oxygen to form 18.2 grams of ferric oxide. How many grams of oxygen reacted?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 8.2 \ grams}}

Explanation:

According to the Law of Conservation of Mass, the mass of the products must equal the mass of the reactants.

  • mass products = mass reactants

In this problem, the reaction is:

iron + oxygen = ferric \ oxygen

  • The reactants are iron and oxygen. We know the mass of the iron sample is 10 grams.
  • The product is ferric oxide. The mass of the ferric oxide sample is 18.2 grams.

10 \ g + oxygen=18.2 \ g

We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.

10 \ g - 10 \ g+ oxygen = 18.2 \ g - 10 \ g

oxygen= 18.2 \ g - 10 \ g

oxygen= 8.2 \ g \\

<u>8.2 grams of oxygen </u>reacted with 10 grams of iron to form 18.2 grams of ferric oxide.

8 0
2 years ago
If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution
satela [25.4K]

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

               Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

          concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

          concentration 2 = (287 x 1.6) / 412

Simplification

          concentration 2 = 459.2 / 412

Result

           concentration 2 = 1.11 M  

5 0
3 years ago
How would an element on the left side of row 2 of the periodic table differ from an element in the middle of the same row?
maw [93]

Explanation:

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7 0
2 years ago
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