Question

A stack of seven different cards are shuffled and spread out face down if three cards are turned face up how many different three card combinations are possible

Answer 1

Answer:35 ways

Step-by-step explanation:

$^nC_{k}$ is the number of ways of choosing $k$ distinct objects from a lot of $n$ distinct objects.

In the given question,

$n=7\\k=3$

$^nC_{k}=\frac{n!}{(n-k)!k!}$

So,$^7C_{3}=\frac{7!}{3!4!}=\frac{210}{6}=35$

So,there are $35$ ways in which three distinct cards can be selecte from seven distinct cards.