I'm assuming you need to evaluate/simplify the equation, so you need to isolate/get x by itself in the equation:
2(3x + 1) = 11 Divide by 2 on both sides
3x + 1 = [11/2 or 5.5] Subtract by 1 on both sides
[make the denominator the same to combine fractions]
3x = Divide by 3 on both sides
x =
Answer:
Length, l = 11 ft.
Width, w = 9 ft.
Step-by-step explanation:
From the given data, the area of the rectangle = 99 ft².
Area of the rectangle = Length, l X Width, w
Here, Length, l = 7 more than twice the width
⇒ Length, l = 7 + 2w
Therefore, Area, A = 99 = (7 + 2w)w
⇒ 99 = 7w + 2w²
⇒ 2w² + 7w - 99 = 0
Solve the Quadratic equation using the formula: x = for the quadratic equation ax² + bx + c = 0.
Therefore, w =
Since, we get:
This gives two values of 'w', viz., w = ,
⇒ w = , -9.
We take the integer values.
If w = -9, then l = 2(-9) + 7
⇒ l = - 18 + 7 = - 11
Therefore, the length, l of the rectangle = - 11 ft.
and the width, w of the rectangle = - 9 ft.
Hence, the answer.
Answer:
15 inches
Step-by-step explanation:
We have that,
Length of the photo = 4 inches and Width of the photo = 6 inches
Also, the width of the image on the calendar = 10 inches
Let, the length on the image of the calendar = x inches.
Since, the ratio of the photo and its image will remain same, we get,
i.e.
i.e. x = 15
Hence, the length of the image of the photo on the calendar is 15 inches.