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2 years ago

Plz help me quickly!!!!!!!!!!

Mathematics

1 answer:

bezimeni [28]2 years ago

4 0

Answer: the tip would be 17.26$

Step-by-step explanation:

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How many gallons of a 90% antifreeze solution must be mixed with 90 gallons of 20% antifreeze to get a mixture that is 80% antif

lozanna [386]

Answer:

540

Step-by-step explanation:

Amount of antifreeze in the 90% solution + amount of antifreeze in the 20% solution = amount of antifreeze in the 80% solution

0.90 x + 0.20 (90) = 0.80 (x + 90)

0.90 x + 18 = 0.80 x + 72

0.10 x = 54

x = 540

You need 540 gallons of 90% antifreeze solution.

7 0

3 years ago

Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi

Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

1 computer : 1 worker : inventory 150 items per hour
1 computer : 2 workers : inventory 200 items per hour
1 computer : 3 workers : inventory 220 items per hour
1 computer : 4+ workers : fewer than 235 items per hour
Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03$

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925$

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98$

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05$

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0

3 years ago

The area of a rectangular of length L width W is given by the formula A =LW. Ann's backyard is rectangular with a length of 27.6

marta [7]

300.84m^2

First, set up the equation

A=27.6•10.9

Next, multiply(use a calculator)

And you get the answer.

^2 means squared.

3 0

3 years ago

What is the GCF of 35 and 49??

Vlada [557]

Answer: 7

Step-by-step explanation: 7x7=49 and 7x5=35

3 0

3 years ago

Read 2 more answers

In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons

GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

$In\:\triangle AOC \:\&\:\triangle BOD$

$AO \cong OB.... (given)$

$\angle AOC \cong\angle BOD$

$(vertical \: \angle s)$

$CO \cong OD.... (given)$

$\therefore \triangle AOC \:\cong\:\triangle BOD$

$(SAS \: postulate)$

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

$AC = BD$

$m\angle OAC = m\angle OBD$

$m\angle OCA = m\angle ODB$

7 0

3 years ago