Answer:
x <2
Step-by-step explanation:
2.5 – 1.2x < 6.5 – 3.2x
Add 3.2x to each side
2.5 – 1.2x+3.2x < 6.5 – 3.2x+3.2x
2.5 +2x < 6.5
Subtract 2.5 from each side
2.5+2x-2.5<6.5-2.5
2x<4
Divide by 2
2x/2 < 4/2
x <2
etc.
Hard to select the correct answers without seeing the choices. Let's check a couple,
Step-by-step explanation:
the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).
so,
1.
(9, 7) to (4, -3)
midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)
2.
(-7, -5) to (2, 1)
midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)
3.
now we have the midpoint and need the second point.
(4, 2) over (3, 4) to (x, y)
3 = (4 + x)/2
6 = 4 + x
x = 2
4 = (2 + y)/2
8 = 2 + y
y = 6
4.
(-2, 1) over (-3, 2) to (x, y)
-3 = (-2 + x)/2
-6 = -2 + x
x = -4
2 = (1 + y)/2
4 = 1 + y
y = 3
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
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If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
