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Kazeer [188]
3 years ago
7

What form of note taking would be MOST beneficial for a visual learner who needs to see the connections between ideas?

Computers and Technology
1 answer:
Svetlanka [38]3 years ago
8 0

Answer:

Think link

Explanation:

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The partners of a small architectural firm are constantly busy with evolving client requirements. To meet the needs of their cli
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Check the explanation

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IPSec-based VPN is configured in two different modes namely

IPSec Tunnel mode and IPSec Transport mode so here we are using IPsec transport mode which is used for end to end communications between a client and a server in this original IP header is remain intact except the IP protocol field is changed and the original protocol field value is saved in the IPSec trailer to be restored when the packet is decrypted on the other side due to this arrangement you need to use application based firewall because there are certain specific rules that can address the particular field (explained above-change in IP protocol field) which at the other end need to be same so at the type of decryption, original IP protocol field can be matched.

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3 years ago
Your baby brother has found the hammer and is eagerly eyeing one of the boxes. Describe and analyze an algorithm to determine if
erastovalidia [21]

Answer:

Question is incomplete.

Assuming the below info to complete the question

You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.

Detailed answer is written in explanation field.

Explanation:

We have to find the reachability using the directed graph G = (V, E)

In this V are boxes are considered to be non empty and it may contain key.

Edges E will have keys .

G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.

Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.

Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.

If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.

After first search from B we can start marking all other vertex of graph G.

So algorithm will be O ( V +E ) = O (n+m) time.

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How many times is the body of the loop executed?
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Answer:

The loop will run 5 times.

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