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nexus9112 [7]
2 years ago
10

________ hackers break into systems for non-malicious reasons such as to test system security vulnerabilities. black-hat gray-ha

t white-hat green-hat
Computers and Technology
1 answer:
Masteriza [31]2 years ago
3 0
<span>These are white-hat hackers. They are typically hired by the company doing the testing as a way of making sure that there are no bugs or holes in the code or program that could be exploited. The ethical hacker would look for ways to get around these issues and helps the company strengthen their programs or sites.</span>
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____ is the encapsulation of method details within a class.
Anestetic [448]

Implementation hiding i<u>s the encapsulation of method details within a class</u>. Implementation can be interpreted as those specifications which can be altered without altering the correctness of an application. Wrapping data/methods within classes (descriptions of the way all objects of this type will look/act) in combination with implementation hiding is called encapsulation. Information users need to know about behaviors should be available without dependence on implementation specifications.

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Karel coding 2.1.4 superkarel cleanup
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hi, try using Code Plans

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it is a free website that include videos and articles on this stuff

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What would you have to know about the pivot columns in an augmented matrix in order to know that the linear system is consistent
Scrat [10]

Answer:

The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

Then satisfying this theorem the system is consistent and has one single solution.

Explanation:

1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

rank(A)

Then the system is consistent and has a unique solution.

<em>E.g.</em>

\left\{\begin{matrix}x-3y-2z=6 \\ 2x-4y-3z=8 \\ -3x+6y+8z=-5  \end{matrix}\right.

2) Writing it as Linear system

A=\begin{pmatrix}1 & -3 &-2 \\  2& -4 &-3 \\ -3 &6  &8 \end{pmatrix} B=\begin{pmatrix}6\\ 8\\ 5\end{pmatrix}

rank(A) =\left(\begin{matrix}7 & 0 & 0 \\0 & 7 & 0 \\0 & 0 & 7\end{matrix}\right)=3

3) The Rank (A) is 3 found through Gauss elimination

(A|B)=\begin{pmatrix}1 & -3 &-2  &6 \\  2& -4 &-3  &8 \\  -3&6  &8  &-5 \end{pmatrix}

rank(A|B)=\left(\begin{matrix}1 & -3 & -2 \\0 & 2 & 1 \\0 & 0 & \frac{7}{2}\end{matrix}\right)=3

4) The rank of (A|B) is also equal to 3, found through Gauss elimination:

So this linear system is consistent and has a unique solution.

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