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3 years ago

Please Please Please Help Me On These 2 Math Questions!!!!! I GIVE THANKS!!!!

Mathematics

1 answer:

Mars2501 [29]3 years ago

3 0

A. After the mod. One wall is “x” longer than original (horizontal in diagram) and the other is “x” shorter (vertical)
(30+x)(30-x)

b. He original area = 30 x 30 = 900 sq. ft.
The mod. Area is (30+6)(30-6) = 36x24= 764 sq. ft.

So the room was largest to begin with when it was a square

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An earthquake can be felt in a circular pattern from the epicenter. If the equation of this pattern is x2 + y2 = 2500, how many

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At a schools field day, students will throw table tennis balls then measure the distance. There are 626 students in the school.

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A museum conducts a survey of its visitors in order to assess the popularity of a device which

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Answer:

The appropriate null hypothesis is $H_0: p \geq 0.2$

The appropriate alternative hypothesis is $H_1: p < 0.2$

The p-value of the test is 0.1057 > 0.05, which means that there is not sufficient evidence that fewer than 20% of the museum visitors make use of the device, and so, it should not be withdrawn.

ii:

The p-value of the test is 0.1057

Step-by-step explanation:

Question i:

The device will be withdrawn if fewer than 20% of all of the museum’s visitors make use of it.

At the null hypothesis, we test if the proportion is of at least 20%, that is:

$H_0: p \geq 0.2$

At the alternative hypothesis, we test if the proportion is less than 20%, that is:

$H_1: p < 0.2$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.2 is tested at the null hypothesis:

This means that $\mu = 0.2, \sigma = \sqrt{0.2*0.8} = \sqrt{0.16} = 0.4$ .

The device will be withdrawn if fewer than 20% of all of the museum’s visitors make use of it. Of a random sample of 100 visitors, 15 chose to use the device.

This means that $n = 100, X = \frac{15}{100} = 0.15$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.15 - 0.20}{\frac{0.4}{\sqrt{100}}}$

$z = -1.25$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.15, which is the p-value of z = -1.25.

Looking at the z-table, z = -1.25 has a p-value of 0.1057.

The p-value of the test is 0.1057 > 0.05, which means that there is not sufficient evidence that fewer than 20% of the museum visitors make use of the device, and so, it should not be withdrawn.

Question ii:

The p-value of the test is 0.1057

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Answer:

Step-by-step explanation:

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210-192=18 cans the girls collected more than the boys

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