Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7. 3k3 + k2 - 3k - 2 -7k3 + k2 + 3k - 16 7k3 - k2 - 3k + 16
2 answers:
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<h2>Answer:</h2>
The ratio of the area of region R to the area of region S is:
The sides of R are in the ratio : 2:3
Let the length of R be: 2x
and the width of R be: 3x
i.e. The perimeter of R is given by:
( Since, the perimeter of a rectangle with length L and breadth or width B is given by:
)
Hence, we get:
i.e.
Also, let " s " denote the side of the square region.
We know that the perimeter of a square with side " s " is given by:
Now, it is given that:
The perimeters of square region S and rectangular region R are equal.
i.e.
Now, we know that the area of a square is given by:
and
Hence, we get:
and
i.e.
Hence,
Ratio of the area of region R to the area of region S is: