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Andre45 [30]
3 years ago
7

A king cobra is 4.237 meters long. Round the length tothe nearest meter

Mathematics
2 answers:
Elanso [62]3 years ago
6 0
The nearest meter is 4 meters because the 7 would round the 3 to a 4, but a 4 wouldn't round up the 2. Even if the 4 rounded up the 2 to a 3, it still wouldn't be enough to round the 4 up to a 5. In other words, 4 and below will not round up anything, but a 5 or above will round up anything (as far as basics go).
Arturiano [62]3 years ago
5 0

Answer:

The length to the nearest meter is 4 meter.

Step-by-step explanation:

Consider the provided information.

A king cobra is 4.237 meters long.

We need to round it to the nearest meter. That means we need to round it to the nearest integer.

The rule of rounding a number is:

If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

If 5, 6, 7, 8, or 9 follow the number, round it up by one digit.

Now consider the number.

At the tenths place the number is 2.

So don't need to change the rounding digit.

Hence, the length to the nearest meter is 4 meter.

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Zina [86]
2x^2 - 2x - 40 = 2x^2 -10x + 8x - 40 = 2x(x - 5) + 8(x - 5)

= (x-5)(2x+8) = 2(x-5)(x+4)
3 0
3 years ago
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately  = 28-17 = 11

5 0
3 years ago
Show work please thanks
Tju [1.3M]
Be more specific on the first one
3 0
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Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund
ser-zykov [4K]

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At the null hypothesis, it is tested if the <u>proportion is of 0.5</u>, that is:

H_0: p = 0.5

At the alternative hypothesis, it is tested if the <u>proportion is different of 0.5</u>, that is:

H_1: p \neq 0.5

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

In which:

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  • p is the value tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are given by:

p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482

The value of the test statistic is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

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Since we have a <u>two-tailed test</u>(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

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Since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

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