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3 years ago

Helppppppppppppppppppppppppppppppp

Mathematics

1 answer:

Ghella [55]3 years ago

4 0

270° × π / 180°
= 3/2π rad
you can rewrite it to 3π/2 radians.

Hope this helps!

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Do you mind o could use a little help

OleMash [197]

5,120........................................

6 0

3 years ago

A square pyramid. The square base has side lengths of 6 inches. The 4 triangular sides have a base of 6 inches and height of 9 i

Marrrta [24]

Answer:

The area of the pyramid’s base is 36 in².

The pyramid has 4 lateral faces.

The surface area of each lateral face is 27 in².

Step-by-step explanation:

"Lateral" means side, so the lateral faces are triangles.

The base is the bottom, which is a square.

To calculate the area of the base, use the formula for area of a square.

$A_{base} = s^{2}$

$A_{base} = (6 in)^{2}$

$A_{base} = 36 in^{2}$

To calculate the area of a lateral face, find the area of a triangle.

$A_{lateral} = \frac{bh}{2}$

$A_{lateral} = \frac{(6 in)(9 in)}{2}$

$A_{lateral} = \frac{54 in^{2}}{2}$

$A_{lateral} = 27 in^{2}$

In a pyramid, the number of lateral faces is the same as the number of sides in the base. The square base as 4 sides, so there are 4 lateral faces.

3 0

3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago

Someone please help with the questions on this picture!! URGENT!!!

tia_tia [17]

Answer:

A) Independent

B) Dependent

Step-by-step explanation:

A) If we take a marble out and put the marble back, it means we have restored the sample to what it was initially and thus it doesn't affect probability of making another selection.

Thus, this is an independent event.

B) A card is taken from a deck of cards without replacement and set aside. Then after that another card is taken from the first sample, this means that the first sample size has now reduced and thus the first card taken affects the probability of the second card to be picked. Thus, this is a dependent event.

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2 years ago

Of the sundaes recently sold at Ice Cream Haven, 4 had nuts and 20 did not. Considering this

Svetlanka [38]

4/24= 1/6
(1/6)*84= 14 had nuts

20/24= 5/6
(5/6)* 84 = 70 no nuts

4 0

2 years ago