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3 years ago

Helppppppppppppppppppppppppppppppp

Mathematics

1 answer:

Ghella [55]3 years ago

4 0

270° × π / 180°
= 3/2π rad
you can rewrite it to 3π/2 radians.

Hope this helps!

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What are the side lengths of a rectangle if the area = 40 in and the perimeter = 48 in

Serggg [28]

4, 10, 4, 10. 10*4 gives area of 40. 10+10+4+4 gives 48 as shown in question

4 0

3 years ago

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I need help with my math to day.‍♀️

ANTONII [103]

Answer:

8x + 1 + 6x + 5 = 90

14x + 6 = 90

14x = 84

x = 6

<DCB is 6x+5

6(6) + 5

36 + 5

8 0

3 years ago

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Brent decorated 1/6 of his sugar cookies with blue frosting 1/4 with yellow frosting and 3/8 with purple frosting which frosting

velikii [3]

If you look at the denominators, they all have a common number they can all multiply into: 24. If you multiply each number in the fraction so that the denominator equals 24, you get this:
1/6 x 4 = 4/24
1/4 x 6 = 6/24
3/8 x 3 = 6/24

Therefore, blue frosting (1/6) is used the least.

Hope this helps:

3 0

2 years ago

Evaluate the expression 263 + 5 when b = 3. 263 +5 = 2(3): +5 =

ExtremeBDS [4]

Given:

The expression is:

$2b^3+5$

To find:

The value of the given expression when $b=3$ .

Solution:

We have,

$2b^3+5$

Substituting $b=3$ in the above expression, we get

$2b^3+5=2(3)^3+5$

$2b^3+5=2(27)+5$

$2b^3+5=54+5$

$2b^3+5=59$

Therefore, the value of given expression at $b=3$ is 59.

7 0

2 years ago

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A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While

Murljashka [212]

Answer:

The expected number of appearance defects in a new car = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = $\nu$ = $= \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61$ = 0.64

$\sigma^{2}$ = variation of E(X) = $\sum (X - \nu) ^{2}P(X)$ = $(3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61$

= $(2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61$ = 0.8704

standard deviation = $\sqrt{\sigma^{2}}$ = $\sqrt{0.8704^{2}}$ = 0.93(approximately)

4 0

3 years ago