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slamgirl [31]
3 years ago
8

Represent the following expressions as a power of the number a (a≠0): c ((a2)−2)5÷(a4a)3

Mathematics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

1/a²⁷

Step-by-step explanation:

Given: $ \frac{((a^2)^{-2})^5}{a^4.a^3} $

We know that when the bases are same the powers can be added. i.,e.,

                                           (xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾

⇒ $ \frac{((a^2)^{-2})^5}{a^4.a^3} \implies \frac{(a^2)^{-10}}{a^7} $

$  \implies \frac{a^{-20}}{a^7} = a^{-20 - 7} = a^{-27} $

Also, $ \frac{x^a}{x^b} = x^{a - b} $

This is nothing but, $ \frac{1}{a^{27}} $.

Note that $ a $ cannot be zero here. The condition is provided in the question as well.

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AysviL [449]
The correct option is (A) x^6 + x^5 - 2x^4  - 2x^3 + 3x^2 + 6x - 9 

Explanation:
The product of two polynomials:
(x^3 + x^2  -3)(x^3 - 2x + 3)

Row1:   x^6       x^5      -3x^3
Row2: -2x^4   -2x^3      6x
Row3:  3x^3     3x^2      -9

Add all of the above rows:
x^6 + x^5 - 3x^3 -2x^4 - 2x^3 + 6x + 3x^3 + 3x^2 -9

x^6 + x^5 - 2x^4  - 2x^3 + 3x^2 + 6x - 9 (Option A)
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3 years ago
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Answer:

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Step-by-step explanation:

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8 0
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
lord [1]

Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph

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Solution:

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at breakeven

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Answer:

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7 0
3 years ago
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