Ask question

Ask question

All categories

3 years ago

7

For a normal distribution , find the area between z=0.54 and z=1.91

2 answers:

Serjik [45]3 years ago

8 0

Find the area under the normal curve for the condition. 5) Find the percent of the area ... 6) Find the percent of the total area under the curve between z = 0.54 and z = 1.91. A) 23.3%. B) 26.7% ... 9) Assume that the weights of quarters are normally distributed with a mean of 5.67 g and a standard deviation. 0.070 g. A vending

.233

maksim [4K]3 years ago

8 0

.2983

You're welcome.

You might be interested in

Find the missing side lengths help please?

Mars2501 [29]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write the equation of a function whose parent function, F(x)=x+5,is shifted 3units to the right

eduard

Got this and not sure but best luck with your studying

6 0

3 years ago

Read 2 more answers

The federal government would like to test the hypothesis that the average age of men filing for Social Security is higher than t

mixas84 [53]

Answer:

The 90% confidence interval is $-0.3433< \mu_1 - \mu_2 < 2.1433$

Step-by-step explanation:

From the question we are told that

The sample mean for men is $\= x_1 = 64.5 \ years$

The sample mean for women is $\= x_2 = 63.6 \ years$

The sample size for men is $n_1 = 35$

The sample size for women is $n_2 = 39$

The standard deviation for men is $s_1 = 3.0$

The standard deviation for women is $s_2 = 3.5$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s_1^2 }{n_1} + \frac{s_2^2}{n_2} }$

=> $SE = \sqrt{\frac{3^2 }{35} + \frac{3.5^2}{39} }$

=> $SE = 0.7558$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * SE$

=> $E = 1.645 * 0.7558$

=> $E = 1.2433$

Generally 90% confidence interval is mathematically represented as

$(\= x_1 - \= x_2) -E < \mu_1 - \mu_2 < (\= x_1 - \= x_2) -E$

=> $(64.5 - 63.6) -1.2433< \mu_1 - \mu_2$

=> $-0.3433< \mu_1 - \mu_2 < 2.1433$

7 0

2 years ago

PLS HELP ILL MARK BRAINLIEST

ki77a [65]

Answer:

(-4,-6),(-2,-5),(0,-4),(4,-2)

Step-by-step explanation:

(x,y)

x represents the x co-ordinate of a point

y represents the y co-ordinate of a point

5 0

3 years ago

Read 2 more answers

In a city, 60% of the residents live in houses and 40% of the residents live in apartments.Of the people who live in houses, 20%

DIA [1.3K]

Answer:

0.75 or 75%

Step-by-step explanation:

The probability that a resident lives in a house and owns their own business is:

$P(H\cap B)=0.6*0.2\\P(H\cap B)=0.12$

The probability that a resident lives in an apartment and owns their own business is:

$P(A\cap B)=0.4*0.1\\P(A\cap B)=0.04$

Therefore, the probability that a person lives in a house, given that they own their own business is:

$P(H|B) = \frac{P(H\cap B)}{P(H\cap B)+P(A\cap B)}\\P(H|B) = \frac{0.12}{0.12+0.04} \\P(H|B) = 0.75$

The probability is 0.75 or 75%.

4 0

3 years ago