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yKpoI14uk [10]
2 years ago
9

Hey, me again I NEED HELP ASAP!

Mathematics
1 answer:
LenKa [72]2 years ago
3 0

THe answer is 36 BOI

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If f(x) = 4x-x², find<br> square root f(3/2)
katrin [286]

Answer:

\frac{\sqrt{15} }{2}

Step-by-step explanation:

\sqrt{f(\frac{3}{2} ) , substitute \frac{3}{2} to x

f(\frac{3}{2} )=4(\frac{3}{2} )-(\frac{3}{2} )^2 = \frac{15}{4} or 3.75

\sqrt{f(\frac{3}{2} )=\sqrt{3.75} = \frac{\sqrt{15} }{2}

6 0
1 year ago
(-(-)(-)(-10x))=-5 solve for x
kirza4 [7]
A negative times a negative is a positive so...

( - ) ( - ) ( - ) ( -10x ) = -5

10x = -5

x = -5/10

x = -1/2
4 0
3 years ago
A volleyball reaches its maximum height of 13 feet, 3 seconds after its served. Which of the following quadratics could model th
julsineya [31]
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.

We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.

8 0
3 years ago
Read 2 more answers
Math question down below
Alja [10]

Answer:

E

E is the only one that ends with 70 and is also all multiples of 6.

4 0
3 years ago
Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s
ozzi

Answer:

10.9\ \text{m/s}^2

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

\mu = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2

La aceleración del bloque es 10.9\ \text{m/s}^2.

8 0
3 years ago
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