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PIT_PIT [208]
3 years ago
7

Which equation is represented by the graph below?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

the 2nd one. I got it correct

Step-by-step explanation:

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A restaurant use 8 1/4 pounds of carrots to make 6 carrot cakes. Frank wants to use the same recipe. How many pounds of carrots
timofeeve [1]

Answer:

1 3/8 pounds

Step-by-step explanation:

divide 8 1/4 by 6

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The data in the table compares x, the number of pages in a chapter, to y, the amount of time, in minutes, spent reading. The fun
ololo11 [35]
21
18=0.86x - 0.09     Put 18 as the y value and solve for x
18.09=0.86x           Add 0.09 on both sides.
21.03=x                  Then divide on both sides by 086

7 0
3 years ago
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Please answer correctly !!!!! Will mark brainliest !!!!!!!!!
SVEN [57.7K]

Answer:

y=(x-5)^2 - 6

Step-by-step explanation:

Subtracting the 5 to the x moves the parabola 5 units to the right. Putting the -6 at the end moves the parabola down 6 units.

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3 years ago
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2(vh)/k=r Solve equation for v in terms of all other variables involved
aivan3 [116]

The equation v in terms of other variables is v = kr/2h

<h3>What is the subject of an equation?</h3>

It is a variable which is expressed in terms of other variables involved in the formula.

Formulas are written so that a single variable, the subject of the formula is on the L.H.S. of the equation. Everything else goes on the right side of the equation. We evaluate the formula by substituting for the literal numbers on the right hand side.

2(vh) / k = r

by cross multiplication

2(vh) = kr

divide both sides by 2h

v = kr/2h

In conclusion, v in terms of other variables is  kr/2h

Learn more about subject of an equation: brainly.com/question/657646

#SPJ1

6 0
1 year ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
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