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stepladder [879]
3 years ago
6

If a gas tank can hold 30 gallons how many gallons does it contain when it is three fifths full

Mathematics
1 answer:
Butoxors [25]3 years ago
6 0
3/5 of 30 is 3/5 times 30/1=90/5=18

answer is 18 gallons
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Help with math please.
lys-0071 [83]
Hello,

The rate of change is the slope (rise/run, y/x). To find that, we use the equation (y2-y1) over (x2-x1). It means take the second "y" and subtract it from the first "y" and the same to "x". If I plug in the numbers, it would be (3-6) over (5-4), and after you subtract, the answer simplifies to: -3/ 1 which is -3. Yay! We got the slope (rate of change) done.

Now let's find the y-intercept by using the formula of point-slope form, 
y-y1= m (slope) (x-x1). This is saying you "y" is subtracted from the first 
"y" of the points which equals the slope (m) times the quantity of "x" subtracted by the first "x" of the points. 

Let's plug the numbers in: y-6 = -3 (x-4). Let's distribute -3 to the parenthesis, and after that it should simplify to: y-6 = -3x + 12. To get "y" by itself, add 6 to both sides: y = -3x +18. We have finally found the slope-intercept equation for those two points (4,6) and (5,3). To then find the y-intercept in this equation, it would be the 18, because -3 is the slope, so that makes 18 the y-intercept.

In conclusion, the rate of change is -3 and the y-intercept is 18. 

I hope this helps!

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3 years ago
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The figure below is a net for a rectangular prism.
lawyer [7]

Answer:

Answer: you've gotten it answered? lmk if you haven't and you're waiting on one

Step-by-step explanation:

7 0
3 years ago
Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
irina1246 [14]
<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

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                      W = 10 - L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

      dA = 0

      10 - 2 L = 0

        L = 5 m

      W = 10 - 5 = 5 m

Area = 5 x 5 = 25 m²

Maximum area is 25 m²

7 0
3 years ago
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Svet_ta [14]
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2 years ago
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Lesechka [4]

Answer:

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