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alekssr [168]
3 years ago
11

Help me pls for extra points it can be a lot

Mathematics
1 answer:
AnnZ [28]3 years ago
8 0
The answer is 2/7 (the first option)
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What two numbers add up to -18 and multiply to 45? (Don’t need to show work)
nordsb [41]
Answer :

It would be -15 and -3
8 0
2 years ago
Read 2 more answers
1/8(5y+64)=1/4(20+2y)
marin [14]
Answer:

<span>y=−24</span>

Explanation:

<span><span>18</span><span>(5y+64)</span>=<span>14</span><span>(2y+20)</span></span>

multiply both sides by 8:

<span>5y+64=2<span>(2y+20)</span></span>

multiply out brackets:

<span>5y+64=4y+40</span>

subtract 4y from both sides:

<span>y+64=40</span>

subtract 64:

<span>y=40−64=−24</span>

<span>y=−<span>24
</span></span>

3 0
3 years ago
Rút gọn bthuc<br> 7x(4y-x) + 4y(y-7x) - (4y^2 -7x)
ale4655 [162]

¢✓¢==¢=

Step-by-step explanation:

==`==¢=¢✓%✓™€✓✓€=€✓€✓

dbshhshs

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3 0
3 years ago
Manny is an online student who currently owns an older car that is fully paid for. He drives, on average, 110 miles per week to
Step2247 [10]

Answer:

The new car costs more

Old car = $5062.125

New car = $7161.357

Step-by-step explanation:

Manny drives an average of 110 miles per week with his old car. The old car gets 16 miles per gallon. The cost per gallon is $2.65 repair and Maintainance costs an average of $740 per year.

For the old car, to find the amount spent on the car we have

110/16 * 2.65 = $18.21875 / week

There are 52 weeks in a year. We have

10.21875*52 = $ 947.375

947.375 + 740

= $1687.375

= 1687.357 * 3

= $5062.125

The new car cost $6500 over a three year loan process.

The car gets 28 miles per gallon. It requires a maintenance f $10 per month. For the new car to find the amount, we have

110*28 * 2.65 *52 = $541.357

541.357 + 10(12) + 6500

= $7161.357

5 0
2 years ago
Find all solutions ​
Anton [14]

Answer:

The solutions of the equation are 0 , π

Step-by-step explanation:

* Lets revise some trigonometric identities

- sin² Ф + cos² Ф = 1

- tan² Ф + 1 = sec² Ф

* Lets solve the equation

∵ tan² x sec² x + 2 sec² x - tan² x = 2

- Replace sec² x by tan² x + 1 in the equation

∴ tan² x (tan² x + 1) + 2(tan² x + 1) - tan² x = 2

∴ tan^4 x + tan² x + 2 tan² x + 2 - tan² x = 2 ⇒ add the like terms

∴ tan^4 x + 2 tan² x + 2 = 2 ⇒ subtract 2 from both sides

∴ tan^4 x + 2 tan² x = 0

- Factorize the binomial by taking tan² x as a common factor

∴ tan² x (tan² x + 2) = 0

∴ tan² x = 0

<em>OR</em>

∴ tan² x + 2 = 0

∵ 0 ≤ x < 2π

∵ tan² x = 0 ⇒ take √ for both sides

∴ tan x = 0

∵ tan 0 = 0 , tan π = 0

∴ x = 0

∴ x = π

<em>OR</em>

∵ tan² x + 2 = 0 ⇒ subtract 2 from both sides

∴ tan² x = -2 ⇒ no square root for negative value

∴ tan² x = -2 is refused

∴ The solutions of the equation are 0 , π

4 0
3 years ago
Read 2 more answers
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