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k0ka [10]
2 years ago
15

Insert grouping symbols so that the given expression has a value of 25. 12 – 7 + 2 • 4 + 6

Mathematics
1 answer:
katovenus [111]2 years ago
4 0
(12-7)+2(4+6) is the one thats value is 25
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In June, a runner ran a mile in 7:45. In September, the runner ran a mile in 5:51. Is the percent of change in time an increase
Mariulka [41]
Since it takes less time in September than in June, this is a DECREASE.  The percent decrease.  The time is different by 114 seconds, divide this by the original time of 465 seconds and then convert to a percent, by multiplying by 100.  You should get 114/465 = 0.245 then x 100 = 24.5% decrease.
7 0
3 years ago
Solve this equation a{6a-2a}=b{2a-3b}
Tcecarenko [31]

The "solution" of the equation would be a pair of numbers ... one
for 'a' and one for 'b' ... that make the equation a true statement.

If the equation has <em><u>two</u></em> variables in it, as this one does, then
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4 0
3 years ago
How much would 1 espresso cost?
IRINA_888 [86]
E = expresso
m = muffins

2e + 3m = 10.....multiply by -2
4e + 2m = 12
----------------
-4e - 6m = -20 (result of multiplying by -2)
4e + 2m = 12
------------------add
-4m = -8
m = -8/-4
m = 2....so muffins cost $ 2 a piece <===

4e + 2m = 12
4e + 2(2) = 12
4e + 4 = 12
4e = 12 - 4
4e = 8
e = 8/4
e = 2......so expresso's cost $ 2 a piece <===

3 0
3 years ago
Un niño de 1,5 de altura divisa una piedra en el suelo con un ángulo de depresión de 37° a qué distancia se encuentra el niño de
Masja [62]

Answer:

english?

Step-by-step explanation:

6 0
2 years ago
HURRY PLEASE
klasskru [66]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

y=0,\:x=6

Step-by-step explanation:

Considering the system of the equations

\begin{bmatrix}2x-7y=12\\ -x+15y=-6\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:2x-7y=12

2x-7y+7y=12+7y

2x=12+7y

Divide both sides by 2

\frac{2x}{2}=\frac{12}{2}+\frac{7y}{2}

x=\frac{12+7y}{2}

\mathrm{Subsititute\:}x=\frac{12+7y}{2}

\begin{bmatrix}-\frac{12+7y}{2}+15y=-6\end{bmatrix}

-\frac{12+7y}{2}+15y=-6

\mathrm{Multiply\:both\:sides\:by\:}2

-\frac{12+7y}{2}\cdot \:2+15y\cdot \:2=-6\cdot \:2

-\left(12+7y\right)+30y=-12

-12+23y=-12

-12+23y+12=-12+12

23y=0

\mathrm{Divide\:both\:sides\:by\:}23

\frac{23y}{23}=\frac{0}{23}

y=0

\mathrm{For\:}x=\frac{12+7y}{2}

\mathrm{Subsititute\:}y=0

x=\frac{12+7\cdot \:0}{2}

x=\frac{12}{2}

x=6

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

y=0,\:x=6

4 0
3 years ago
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