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Alexeev081 [22]
3 years ago
5

Let f(x) = cos(x) + 2x. Where does f have critical points?

Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

<em>f</em> has no critical points.

Step-by-step explanation:

We are given:

f(x)=\cos(x)+2x

A function has critical points whenever its derivative equals 0 or is undefined.

Differentiate the function:

f'(x)=-\sin(x)+2

Since this will never be undefined, solve for its zeros:

0=-\sin(x)+2

Hence:

\displaystyle \sin(x)=2

Recall that the value of sine is always between -1 and 1.

Thus, no real solutions exist.

Therefore, <em>f</em> has no critical points.

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