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2 years ago

If (14,25) and (9,-10) are two anchor points on a trend line, then find the equation of the line.

Mathematics

1 answer:

posledela2 years ago

3 0

Answer:

y= 7x-73

Step-by-step explanation:

the equation form is y=mx+c where m is the slope and c a constant

m= (25-(-10))/14-9 = 35/5 = 7

so y= 7x+c

replace x and y by 14 and 25 respectively

25 = 7*14+c

c= 25-7*14

c = -73

so y= 7x-73

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AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC

sergejj [24]

Answer:

$7x+5y-48=0$

Step-by-step explanation:

Refer the attached figure .

We are given a line AB

Point A $=(x_1,y_1) = (-3,-1)$

Point B $=(x_2,y_2) = (4,4)$

Formula for slope 'm' when two points are given :

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting thew values

$m=\frac{4-(-1)}{4-(-3)}$

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So, By property - perpendicular slopes are negative reciprocals of each other.

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Point B = (4,4)

Formula of equation of line : $y-y_1=m(x-x_1)$

$y-4=\frac{-7}{5}(x-4)$

$5(y-4)=-7(x-4)$

$5y-20=-7x+28$

$7x+5y-20-28=0$

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