Answer: Part A is 2 and 6 Part B is 2
Step-by-step explanation:
Part A: Here is the explanation. So, you started at with the expression 3x^2+8x+4 and when you're are factoring, you have 3x^2+px+pq+4. You can substitute the p and q for 6 and 2. What they did is they replaced 8x with px+qx. To get 8x, p needs to be 6 and q needs to be 2, or the other way around. TIP: The numbers just have to add up to 8 on this one. It doesn't have to be 6 and 2.
Part B: Here is what I got so far... 3x(x+r) is 3x^2+3xr. Also, s(x+r) is sx+sr. The equation becomes, 3x^2+3xr+sx+sr. R can be 2 and s can be 2. Here is my reasoning: The original expression was 3x^2+8x+4. We already have the 3x^2, so now we need to find what the others are by determining what r and s equal. R and s can both be 2 to make four. 2x2 is 4. Let's see if it can make 8. 3xr becomes 6x and sx becomes 2x. 6x+2x is 8x.
For the<span> geometric sequence, it has two forms of formula
</span>
<span>We are interested in the recursive formula now
</span>
<span>
{-80, 20, -5, ...}
The common ratio is (20/-80)=(-5/20)=-1/4=-0.25
So our r</span><span>ecursive formula would be
</span>
I hope that
helps!
9 1/7 lb
You can convert the mixed numbers to solve it easier! :)
Answer:
The x-coordinate of point P is 6
Step-by-step explanation:
we have
A (2,3) and B (8,0)
we know that
Point P portions the segment AB in the ratio 2 to 1
so
and
where
AP_x represent the distance between the points A and P in the x-coordinates
AB_x represent the distance between the points A and B in the x-coordinates
The x-coordinate of P is equal to
where
A_x represent the x-coordinate of A
substitute the values
therefore
The x-coordinate of point P is 6