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nordsb [41]
4 years ago
15

If the unit price for watermelon is $0.24 per pound and Jared pays $1.68 for a watermelon, how many pounds does his watermelon w

iegh?
Mathematics
2 answers:
zmey [24]4 years ago
5 0
The answer is 7 pounds.

To answer this you create a proportion like this
\frac{0.24}{1}  =  \frac{1.68}{?}
The top values represent the cost and the bottom values represent the weight in pounds

You cross multiply and divide to get 7 pounds, which is the answer
Vanyuwa [196]4 years ago
4 0
The watermelon weighs 7 pounds

Proof: 

remove the decimal points then divide 168 by 24

168/24 = 7

The watermelon weighs 7 pounds
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Solve (7.93205×10^8) • (3.12×10^-8)
lord [1]

Answer:

2.4747996 * 10^1

Step-by-step explanation:

When working in scientific notation, (a * 10^b) * (c*10^d)

Multiply a*c   then add 10 ^(b+d)

Then check that the product of ac is between 1 and 10, if not then we need to adjust so that it is

(7.93205×10^8) • (3.12×10^-8)

(7.93205) • (3.12) =24.747996

10^(8-8) = 10^0

24.747996  needs to be adjusted to be between 1 and less than 10

we move the decimal 1 to the left so we add 1 to the exponent

2.4747996 * 10^0+1

2.4747996 * 10^1

7 0
4 years ago
Read 2 more answers
The gestation period of a donkey is about 365 days . About how many weeks is 365 days?
yanalaym [24]
There are about 52 weeks

8 0
3 years ago
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What is the mode of the data set? Hours of Sleep 6, 7, 8, 9 or 10.
kvv77 [185]

Answer:

there is no mode

Step-by-step explanation:

mode=most common

there is no number written more than 1

if it was 6,6,7,8

the mode would have been 6

8 0
4 years ago
Read 2 more answers
What is 0.004 divided by 0.05
Korvikt [17]
When u divide 0.004 by 0.05 you will get 0.08 as the quotient.
 

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4 0
3 years ago
The operating costs for each machine for one day have an unknown distribution with mean 1610 and standard deviation 136 dollars.
Lelechka [254]

Answer:

The standard deviation for the sample mean distribution is \sigma_{\bar{X}}=\frac{136}{\sqrt{45}}=\frac{136\sqrt{5}}{15} \approx 20.274

Step-by-step explanation:

The central limit theorem states that if you have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population then the distribution of the sample means will be approximately normally distributed.

For the random samples we take from the population, we can compute the standard deviation of the sample means:

\sigma_{\bar{X}}=\frac{\sigma}{\sqrt{n}}

From the information given

The standard deviation σ = 136 dollars

The sample n = 45

Thus,

\sigma_{\bar{X}}=\frac{136}{\sqrt{45}}=\frac{136\sqrt{5}}{15} \approx 20.274

The standard deviation for the sample mean distribution is \sigma_{\bar{X}}=\frac{136}{\sqrt{45}}=\frac{136\sqrt{5}}{15} \approx 20.274

7 0
4 years ago
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