Question

Huntington's disease is an inherited autosomal dominant disorder that can affect both men and women. Imagine a couple has had seven children, and later in life, the husband develops Huntington's disease. He is tested and it is discovered he is heterozygous for the disease allele, Hh. The wife is also genetically tested for the Huntington's disease allele, and her test results show she is unaffected, hh.
1. What is the percent probability that the first child of this couple will have Huntington's disease?
_______%
2. What is the probability that any two of the seven children will have Huntington's disease?

_______%

Answer 1

Answer:

50 %

16.4%

Explanation:

Huntington's disease: is an autosomal dominant disorder.

given

male = Hh

female = hh

H =dominant allele

h = recessive allele

All child inherit one allele from each parent, one from father and one from mother.

So  parents are

1).

Hh and hh

F1 progeny are  (Hh, Hh, hh and hh)

50% show Huntington's disease ( Hh, Hh)

so there are 50% chances that first child have Huntington's disease

2).

Any two of the seven children will have Huntington's disease

=16.4%