A 62.5 kg carpenter at a construction site plans to swing in a circular arc from one roof top to an adjacent roof at the end of
1 answer:
Answer:
v = 9.45 m/s
Explanation:
given,
mass of the carpenter = 62.5 Kg
length of rope = 13.4 m
Capable of exerting force = 1034 N
centripetal force acting on the body
F =4.664 v² N
Gravitational force on her =
F = m g
F = 62.5 x 9.81
F = 613.125 N
now,
4.664 v² + 613.125 = 1034
4.664 v² = 420.875
v² = 90.24
v = 9.45 m/s
Maximum speed which she can tolerate = v = 9.45 m/s
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Answer:
Explanation:
We must separate the motion into two parts, the first when the rocket's engines is on and the second when the rocket's engines is off. So, we need to know the height () that the rocket reaches while its engine is on and we need to know the distance (
) that it travels while its engine is off.
For solving this we use the kinematic equations:
In the first part we have:
and the final speed is:
In the second part, the final speed of the first part it will be the initial speed, and the final speed is zero, since gravity slows it down the rocket.
So, we have:
The sum of these heights will give us the total height, which is known:
This is the time that its needed in order for the rocket to reach the required altitude.
Answer
a) charge of the sodium ion is,
q = n e
q = 2.68 x 10¹⁶ x 1.6 x 10⁻¹⁹
q = 4.288 x 10⁻³ C
charge of the chlorine ion is,
q' = n e
q' = 3.92 x 10¹⁶ x 1.6 x 10⁻¹⁹
q' = 6.272 x 10⁻³ C
the current
b) positive ion moves toward negative electrode hence direction of will be in the direction toward negative electrode.
Capacitor in series with a 100Ω resistor and a 18.0 mH inductor will give a resonance frequency of 1000 Hz is 1.38F
Resonance Frequency of a combination of Series LCR circuit is the frequency at which resonance is achieved in a circuit.
Resonance Frequency of a combination of Series LCR circuit is given by:
f = 1 / 2π
where, f is the resonance Resonance Frequency of a combination of Series LCR circuit
L is the Inductance of the inductor
C is the capacitance of the capacitor
Given,
f = 1000Hz
L = 18.0 mH = 0.018H
R = 100Ω
C = ?
On substituting the values in the above-mentioned formula:
1000 = 1 / 2π
2π = 0.001
On solving, C = 1.38 F
Hence, the capacitance of the given capacitor is 1.38F.
Learn more about Resonant frequency here, brainly.com/question/13040523
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