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2 years ago

4.

Physics

2 answers:

Nady [450]2 years ago

7 0

Answer: It's A) S C A N N I N G <em>V R O T H E R S</em>

Explanation: I know because I took the test and got it correct/FLVS, you're welcome.

Tanzania [10]2 years ago

4 0

I think it’s watching your mirrors so C

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A 20-N force acts on an object with a mass of 2.0kg. what is the objects acceleration?

ale4655 [162]

Answer:

10 m/s^2

Explanation:

Equation: F = ma.

a = acceleration

m = mass

F = force

Because we are trying to find acceleration instead of force we want to rearrange the equation to solve for a which is F/m = a.

F = 20

m = 2

a = ?

a = F/m

a = 20/2

a = 10 m/s^2

7 0

2 years ago

Read 2 more answers

A football player runs directly down the field for 45m before turning to the right at an angle of 25 degrees from his original d

Fiesta28 [93]

............................................................................... Hello wonderful person <3

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2 years ago

A particle of charge 2.0 x 10^-8C experiences an upward force of magnitude 4.0 x10^-6 when it is placed in a particular point in

koban [17]

Answer:

a) The electric field at that point is $2.0\times 10^{2}$ newtons per coulomb.

b) The electric force is $2.0\times 10^{-6}$ newtons.

Explanation:

a) Let suppose that electric field is uniform, then the following electric field can be applied:

$E = \frac{F_{e}}{q}$ (1)

Where:

$E$ - Electric field, measured in newtons per coulomb.

$F_{e}$ - Electric force, measured in newtons.

$q$ - Electric charge, measured in coulombs.

If we know that $F_{e} = 4.0\times 10^{-6}\,N$ and $q = 2.0\times 10^{-8}\,C$ , then the electric field at that point is:

$E = \frac{4.0\times 10^{-6}\,N}{2.0\times 10^{-8}\,C}$

$E = 2.0\times 10^{2}\,\frac{N}{C}$

The electric field at that point is $2.0\times 10^{2}$ newtons per coulomb.

b) If we know that $E = 2.0\times 10^{2}\,\frac{N}{C}$ and $q = 1.0\times 10^{-8}\,C$ , then the electric force is:

$F_{e} = E\cdot q$

$F_{e} = \left(2.0\times 10^{2}\,\frac{N}{C} \right)\cdot (1.0\times 10^{-8}\,C)$

$F_{e} = 2.0\times 10^{-6}\,N$

The electric force is $2.0\times 10^{-6}$ newtons.

7 0

2 years ago

When you are driving on a rural road, if your right wheels run off the pavement, you should hold the steering wheel firmly and

julia-pushkina [17]

Answer:

C). Take your foot off the gas pedal. Then brake lightly until you are moving at low speed.

Explanation:

While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the gas pedal, then apply brake lightly until we are moving at a low speed.

When our wheels drift off the pavement area, we should not panic and yank. And instead of turning the wheel back in the left direction towards the road, it is always safer to take off our foot from the gas pedal and then apply brakes slowly. When our vehicle slows down check the incoming traffic behind us and then we should slowly move back on to the pavement.

7 0

2 years ago

In the diagram shown, satellite S moves in a circular orbit around the Earth (E) in a counterclockwise direction.

zubka84 [21]

The characteristics of the velocity vector used to find the results for the direction of acceleration and velocity are:

Acceleration is towards the center of the circle

The velocity is tangent to the circle counterclockwise.

Newton's Second Law establishes a relationship between force, mass and acceleration of bodies.

<h3>Centripetal acceleration. </h3>

In the case of circular motion there is a constant change in the direction of the velocity vector, even when its module remains constant, this change in direction points towards the center of the circle, so that the module is constant.

They indicate that the satellite is moving counterclockwise, therefore the speed must go to the left (counterclockwise) tangential to the circle.

In conclusion using the characteristics of the velocity vector we can find the results for the direction of acceleration and velocity are:

Acceleration is towards the center of the circle

The velocity is tangent to the circle counterclockwise.

Learn more about centripetal acceleration here: brainly.com/question/25243603

6 0

1 year ago