Answer:
60 m
Explanation:
Since it goes 6 m per second, and it goes for 10 seconds, then you'd just multiply 6 x 10, to get that the ball would roll 60 m in 10 seconds.
Answer:
The explosive force experienced by the shell inside the barrel is 23437500 newtons.
Explanation:
Let suppose that shells are not experiencing any effect from non-conservative forces (i.e. friction, air viscosity) and changes in gravitational potential energy are negligible. The explosive force experienced by the shell inside the barrel can be estimated by Work-Energy Theorem, represented by the following formula:
(1)
Where:
- Explosive force, measured in newtons.
- Barrel length, measured in meters.
- Mass of the shell, measured in kilograms.
, - Initial and final speeds of the shell, measured in meters per second.
If we know that , , and , then the explosive force experienced by the shell inside the barrel is:
The explosive force experienced by the shell inside the barrel is 23437500 newtons.
Since there is no friction on the ramp so there is no loss of energy in terms of frictional loss
So here we can use mechanical energy conservation law in this case
so here we will have
here we know that
also we know that
now we will have
now by solving above equation we have
so here as we know all identical balls are released from same height so all balls must have same speed at the end