Question

Current passes through a solution of sodium chloride. In 1.00 s , 2.68× 10 16 Na + ions arrive at the negative electrode and 3.92× 10 16 Cl − ions arrive at the positive electrode. Part A What is the current passing between the electrodes? I I = nothing mA SubmitRequest Answer Part B What is the direction of the current? What is the direction of the current? outward the negative electrode toward the negative electrode SubmitRequest Answer Provide Feedback Next

Answer 1

Answer

a) charge of the sodium ion is,

q = n e

q = 2.68 x 10¹⁶ x 1.6 x 10⁻¹⁹

q = 4.288 x 10⁻³ C

charge of the chlorine ion is,

q' = n e

q' = 3.92 x 10¹⁶ x 1.6 x 10⁻¹⁹

q' = 6.272 x 10⁻³ C

the current

$i = \dfrac{q}{t} + \dfrac{q'}{t}$

$i = \dfrac{4.288 \times 10^{-3}}{1} + \dfrac{6.272 \times 10^{-3}}{1}$

$i = 10.56 \times 10^{-3}$

b) positive ion moves toward negative electrode hence direction of will be in the direction toward negative electrode.