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scoundrel [369]
3 years ago
5

Sarah has a make your own candle set that includes a block of wax in the shape of a rectangular prism. The block of wax has a le

ngth of 8 inches, a width of 6 inches, and a height 3 inches. She wants to make 4 cylindrical candles called pillar candles. Each candle mold will have a diameter of three inches and a height of 6 inches. Does she have enough wax to make the pillar candles? If not, how many complete candles can she make

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0

Answer:

She doesn't have enough wax to make 4 candles, but she does have enough to make 3 whole candles

Step-by-step explanation:

Please refer to the attached image for explanations

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Find the cube roots of 27(cos 330° + i sin 330°)
Aleksandr-060686 [28]

Answer:

See below for all the cube roots

Step-by-step explanation:

<u>DeMoivre's Theorem</u>

Let z=r(cos\theta+isin\theta) be a complex number in polar form, where n is an integer and n\geq1. If z^n=r^n(cos\theta+isin\theta)^n, then z^n=r^n(cos(n\theta)+isin(n\theta)).

<u>Nth Root of a Complex Number</u>

If n is any positive integer, the nth roots of z=rcis\theta are given by \sqrt[n]{rcis\theta}=(rcis\theta)^{\frac{1}{n}} where the nth roots are found with the formulas:

  • \sqrt[n]{r}\biggr[cis(\frac{\theta+360^\circ k}{n})\biggr] for degrees (the one applicable to this problem)
  • \sqrt[n]{r}\biggr[cis(\frac{\theta+2\pi k}{n})\biggr] for radians

for  k=0,1,2,...\:,n-1

<u>Calculation</u>

<u />z=27(cos330^\circ+isin330^\circ)\\\\\sqrt[3]{z} =\sqrt[3]{27(cos330^\circ+isin330^\circ)}\\\\z^{\frac{1}{3}} =(27(cos330^\circ+isin330^\circ))^{\frac{1}{3}}\\\\z^{\frac{1}{3}} =27^{\frac{1}{3}}(cos(\frac{1}{3}\cdot330^\circ)+isin(\frac{1}{3}\cdot330^\circ))\\\\z^{\frac{1}{3}} =3(cos110^\circ+isin110^\circ)

<u>First cube root where k=2</u>

<u />\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(2)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+720^\circ}{3})\biggr]\\3\biggr[cis(\frac{1050^\circ}{3})\biggr]\\3\biggr[cis(350^\circ)\biggr]\\3\biggr[cos(350^\circ)+isin(350^\circ)\biggr]

<u>Second cube root where k=1</u>

\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(1)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+360^\circ}{3})\biggr]\\3\biggr[cis(\frac{690^\circ}{3})\biggr]\\3\biggr[cis(230^\circ)\biggr]\\3\biggr[cos(230^\circ)+isin(230^\circ)\biggr]

<u>Third cube root where k=0</u>

<u />\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(0)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ}{3})\biggr]\\3\biggr[cis(110^\circ)\biggr]\\3\biggr[cos(110^\circ)+isin(110^\circ)\biggr]

4 0
2 years ago
Which of these expressions are equivalent to -2(x-5)
grin007 [14]

Hey there!

-2(x - 5)


DISTRIBUTE -2 WITHIN the PARENTHESES

= -2(x) - 2(-5)


= -2x + 10


Therefore, your answer is: -2x + 10


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

8 0
2 years ago
A:180<br> B:30<br> C:170<br> D:25
tekilochka [14]

Answer:

The answer is B. Hope this helps!

Step-by-step explanation:

105 degrees is from a b to d and a b to c is 75 and 105 - 75 =30.

7 0
3 years ago
Read 2 more answers
2. Which expression is equivalent to 3(4x + 10 = 2+3)?
ololo11 [35]

Answer: ask ggle it gives you the answer

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Be quick! i will mark the correct one brainliest :)
Inessa [10]
Whats the queastion think
3 0
3 years ago
Read 2 more answers
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