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4 years ago

What is the solution to the system of equation -2x+6y=-38 3x-4y=32

Mathematics

2 answers:

Alla [95]4 years ago

5 0

Answer:

x= 4

y= -5

Step-by-step explanation:

-2x+6y=-38 equation 1

3x-4y=32 equation 2

using equation 1 we have:

-2x+6y=-38

6y +38 = 2x

3y + 19 = x equation 3

using equation 3 in equation 2 we have:

3(3y + 19) - 4y = 32

9y + 57 -4y =32

5y = 32 -57

5y = -25

y= -25/5

y = -5

so we have:

3y + 19 = x

3(-5) +19 = x

x= 4

hram777 [196]4 years ago

3 0

Answer:

solution set of the system of equations is (4, -5)

Step-by-step explanation:

System of the equations is given as

-2x + 6y = -38

By dividing this equation by 2

-x + 3y = - 19 ---------(1)

3x - 4y = 32 ------(2)

Now we multiply equation (1) by 3 and add it to equation (2)

3(-x + 3y) + (3x - 4y) = 3(-19) + 32

-3x + 9y + 3x - 4y = -57 + 32

5y = -25

y = -5

Now we put y = -5 in equation (1)

-x + 3(-5) = -19

-x - 15 = -19

-x = 15 - 19

-x = -4

x = 4

Therefore, solution set of the system of equations is (4, -5)

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3 years ago

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3 years ago

Read 2 more answers

Which two values of x are roots of the polynomial below? 3x2-3x+1

QveST [7]

Answer:

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

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we have

$3x^2-3x+1$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

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$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

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$x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}$

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$i=\sqrt{-1}$

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3 years ago

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The answer is: " 105 mi. " .
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Explanation:
____________________________________________
Note that: "that amount of time" is "3 hours".

→ $\frac{35 mi}{h} * \frac{3h}{1}$ = ? ;

→ The units of "h" (for "hour/s") cancel out to "1" ; since ("h/h = 1") ;

→ and we are left with (35 * 3) mi. = 105 mi.
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The answer is: " 105 mi. " .
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3 years ago