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2 years ago

Which is a factor of z3 - z2 - 9z + 9?

Mathematics

1 answer:

lara31 [8.8K]2 years ago

3 0

Z²(z-1)-9(z-1)
= (z²-9)(z-1)
= (z+3)(z-3)(z-1)

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1/2x + 3/2 (x + 1) - 1/4 = 5

kompoz [17]

The answer to your problem is x= 15/8 as decimal form it’s 1.875

6 0

2 years ago

Please help and leave explanation

chubhunter [2.5K]

Answer: x = 150°

Step-by-step explanation:

The tangent intersects the circle's radius at a 90° angle, so ∠OAC = ∠OBC = 90°.

AOBC is a quadrilateral and we know that sum of interior angles of quadrilateral equals to 360°.

Now,

∠OAC + ∠OBC + ∠AOB + ∠ACB = 360°

90° + 90° + x + 30° = 360°

210° + x = 360°

x = 360° - 210°

x = 150°

7 0

2 years ago

An inch is about 2.54 centimeters. Write an expressions wich estimate the number of centimeters in x inches.Then centimeters the

Alborosie

2.54(x) = cm in inches
2.54(12) = 30.48
12 inches = 30.48 cm

6 0

2 years ago

What is the solution to -4(8 – 3x) >_ 6x – 8?

Vsevolod [243]

Answer:

x ≥ 4

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Step-by-step explanation:

Step 1: Define inequality

-4(8 - 3x) ≥ 6x - 8

Step 2: Solve for x

Distribute -4: -32 + 12x ≥ 6x - 8
Subtract 6x on both sides: -32 + 6x ≥ -8
Add 32 on both sides: 6x ≥ 24
Divide 6 on both sides: x ≥ 4

Here we see that x can be any value greater than or equal to 4.

3 0

2 years ago

An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.

Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

$P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)= \frac{10}{20}=\frac{1}{2}\\P(W)= \frac{2}{20}=\frac{1}{10}$

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

$P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04$

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

$P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25$

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

$P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40$

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0

2 years ago